4c^2+4c+1=9

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Solution for 4c^2+4c+1=9 equation:


Simplifying
4c2 + 4c + 1 = 9

Reorder the terms:
1 + 4c + 4c2 = 9

Solving
1 + 4c + 4c2 = 9

Solving for variable 'c'.

Reorder the terms:
1 + -9 + 4c + 4c2 = 9 + -9

Combine like terms: 1 + -9 = -8
-8 + 4c + 4c2 = 9 + -9

Combine like terms: 9 + -9 = 0
-8 + 4c + 4c2 = 0

Factor out the Greatest Common Factor (GCF), '4'.
4(-2 + c + c2) = 0

Factor a trinomial.
4((-2 + -1c)(1 + -1c)) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(-2 + -1c)' equal to zero and attempt to solve: Simplifying -2 + -1c = 0 Solving -2 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1c = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1c = 0 + 2 -1c = 0 + 2 Combine like terms: 0 + 2 = 2 -1c = 2 Divide each side by '-1'. c = -2 Simplifying c = -2

Subproblem 2

Set the factor '(1 + -1c)' equal to zero and attempt to solve: Simplifying 1 + -1c = 0 Solving 1 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1c = 0 + -1 -1c = 0 + -1 Combine like terms: 0 + -1 = -1 -1c = -1 Divide each side by '-1'. c = 1 Simplifying c = 1

Solution

c = {-2, 1}

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